I can never remember how to do replaces in Visual Studio using regular expressions, so here’s a quick example.
I’ve got 30 classes that implement BasePage. I want to change this:
public class VariationsPage : BasePage
to this:
public class VariationsPage : BasePage<VariationsPage>
The regex should find:
public class {.*} \: BasePage
and replace with:
public class \1 \: BasePage<\1>
Edit: the syntax changed in Visual Studio 2012 and onwards! Instead of {.*} and \1 it is now (.*) and $1.
Matt's work blog 
thank you ! it helped me :-)
doesn’t work , need help!!!
i want to find:
RaisePropertyChanged(“x”);
and to replace with:
RaisePropertyChanged(=> x);
x-can be all string
Hello gili,
What version of Visual Studio are you using? I think my blog post was written using Visual Studio 2010. It looks like the syntax has changed to use $1 for substitutions instead of \1, according to this page:
https://msdn.microsoft.com/en-us/library/2k3te2cs%28v=vs.120%29.aspx
“For example, the grouped regular expression (\d)([a-z]) finds four matches in the following string: 1a 2b 3c 4d. The replacement string z$1 converts that string to z1 z2 z3 z4> The equivalent syntax in Visual Studio 2010 is {:z}([a-z]) for the grouped regular expression and z\1 for the replacement string.”
I have just tested this on Visual Studio 2013 (which is the only version I have installed), and this works:
Find:
RaisePropertyChanged\(“(.*)”\);
Replace:
RaisePropertyChanged(=> $1);